JAX-RS @QueryParam with @DefaultValue – Jersey

In this tutorial we are going to see how set  default value to query parameters (@QueryParam) in RESTful web service using @DefaultValue

Create maven web application project and add Jersey dependency in pom.xml. Find Jersey 2.x maven dependency configuration below. If you are new to maven refer our maven tutorials.

Jersey 2.x dependency in pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
  <name>RestTutorials Maven Webapp</name>
      <!-- JAX-RS -->
        <!-- Jersey 2.19 -->

QueryParamService .java

package com.ehowtonow.webservice;

import javax.ws.rs.DefaultValue;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.QueryParam;
import javax.ws.rs.core.Response;

public class QueryParamService {

 public Response getTutorial(
   @DefaultValue("www.ehowtonow.com") @QueryParam("site") String site,
   @DefaultValue("Web Service Tutorial") @QueryParam("tutorial") String tutorial,
   @DefaultValue("1") @QueryParam("rank") int rank) {
  return Response
    .entity("Web Site : " + site + "  Tutorial : " + tutorial
      + " Rank : " + rank).build();

In above class @QueryParam used to get the value of URL query parameter into Java Class. If there is no query param in URL then default value set to the corresponding fields using @DefaultValue annotation

Configure Jersey 2.x Servlet dispatcher

 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

	<display-name>Restful Webservice Example</display-name>


Now you can run the service and access the service by calling the following URL




In first url we didn’t pass any query param value. JAX-RS will set the default value from @Default annotation to query parameters.

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